Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 166 3 a Solution Created 2026-09-24 Updated 2026-09-24
For a linear form over a number field , define its height to be the projective height of its coefficient vector:The product formula makes this independent of multiplying by a nonzero scalar.
The Siegel lemma says the following. Let , let be linear forms in variables with , and suppose for every , where . Then there is a nonzero annihilated by all the forms and satisfying
Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 166 3 b Solution Created 2026-09-24 Updated 2026-09-24
Writeso there are unknown integer coefficients. Let be the number of integers withFor each such , impose the linear equation over where is the normalized derivative of a polynomial. The coefficient of is and that of is . The local definition of projective height, together with , givesfor a constant depending only on .
There are forms over the degree- field , andMoreover . Applying Siegel lemma gives a nonzero integral coefficient vector withbecause the exponent is bounded in terms of and every fixed power of is at most exponential in . These have all the required vanishing normalized derivatives.
Thue-Siegel auxiliary polynomial Created 2026-09-24 Updated 2026-09-24
For an algebraic number of degree and a small , Siegel lemma constructs integer polynomials of degree at most and exponentially bounded coefficients for which has a zero at of order close to . A Wronskian then prevents every specialization from having a high-order zero at a rational point. This is the auxiliary-polynomial mechanism in the Thue-Siegel method.