The quaternionic projective space is the space of one-dimensional right quaternion subspaces of . Equivalently it is the quotient of the unit sphere by simultaneous right multiplication by unit quaternions. Its coordinate filtration has one open cell in each dimension , for . Hence its cellular cohomology is in those dimensions and zero otherwise.
Let be the quaternionic tautological line bundle. Its unit sphere bundle is , with fibre . The Gysin sequence of a sphere bundle shows that multiplication by its Euler class is an isomorphism from to for . Choose the generator . Its powers generate every nonzero positive degree, giving the cohomology ring of quaternionic projective space
This also accounts for .
First take . Under the coordinate inclusion , the pulled-back quaternionic line is the quaternionic extension of the complex tautological line . As a complex rank-two bundle it is : a transition scalar acts on the two complex coordinates of a quaternion by and . Put , the degree-two generator of the cohomology ring of complex projective space. The Whitney sum formula for Chern classes gives
Here the Euler class of a complex vector bundle is its top Chern class, using the complex orientation. In particular this degree-four pullback has coefficient one; it is not a multiple of larger absolute value. The compatible tautological bundles on the projective filtrations give the same equality for every , and multiplicativity then determines the whole ring map:
It is zero whenever . These facts are the complex inclusion into quaternionic projective space.
For an odd prime , the Steenrod reduced powers are natural stable cohomology operations
They satisfy , the Cartan formula, when , and when . In particular, on one has and for . The Cartan formula and the binomial theorem give
Pass to the infinite projective spaces, where , , is injective. The equality just obtained determines the Steenrod powers on quaternionic projective space; restricting to the finite spaces gives
with coefficients modulo and powers above set to zero. In particular , , and for . The infinite-space argument matters: the finite inclusion cannot detect those degrees for which .
Finally put and . Both have reduced cohomology in degrees and zero otherwise. Choose integral generators for whose pullbacks under the quotient map are , and suspended integral generators for from .
Use . Naturality for the quotient and the formula above give
Stability under the suspension isomorphism instead gives
Any homotopy equivalence would induce isomorphisms on the rank-one integral groups, so and with . Reducing modulo five and commuting with would require in . Neither nor equals or modulo five. Therefore
The essential point is that integral generator signs constrain Steenrod comparisons. Arbitrary changes of basis over could rescale these two nonzero coefficients into agreement; a genuine equivalence must also preserve the integral lattices, where only the two signs are available.
Steenrod reduced power 2026-10-06
For odd prime , the reduced powers are natural stable cohomology operations. They satisfy , the Cartan formula, and the instability conditions for and for . In particular, a degree-two class has and no higher nonzero reduced power. Stability lets these operations detect distinctions between suspensions whose additive cohomology and cup products agree.