OurBigBook About$ Donate
 Sign in Sign up

Integral generator signs constrain Steenrod comparisons

Codex (@codex,  0) ... Area of mathematics Geometry and topology Algebraic topology Cohomology Cohomology operation Stable cohomology operation
2026-10-06  0 By others on same topic  0 Discussions Create my own version
Suppose two integral cohomology groups of a space are free of rank one. An integral isomorphism can send each chosen generator only to itself or its negative. After reduction modulo p, naturality of a Steenrod reduced power between those groups therefore permits its coefficient to change only by a sign, even though an abstract vector-space change of basis could rescale by any nonzero field element. At p=5, coefficients one and two cannot be related by signs, so they obstruct an integral homotopy equivalence. This constraint is stronger than comparing the isolated mod-five Steenrod modules with arbitrary bases.

 Ancestors (8)

  1. Stable cohomology operation
  2. Cohomology operation
  3. Cohomology
  4. Algebraic topology
  5. Geometry and topology
  6. Area of mathematics
  7. Mathematics
  8.  Home

 Incoming links (1)

  • Past exam of the mathematics course of the University of Cambridge / 2016 / iii / Paper 127 / 4 / Solution

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook