SU(3) triplet-octet decomposition
= SU(3) triplet-octet decomposition
{c}
{title2=$\mathbf3\otimes\mathbf8=\mathbf{15}\oplus\overline{\mathbf6}\oplus\mathbf3$}
The summands have <Dynkin labels> $(2,1)$, $(0,2)$ and $(1,0)$. Convolving the triplet and octet <weight diagrams> and applying <highest-weight character subtraction> removes these three characters in that order. Their dimensions $15+6+3=24$ match the product.
// Target: quantum-field-theory.bigb