SU(3) triplet-octet decomposition ($3\otimes 8=15\oplus \overline{6}\oplus 3$)

The summands have Dynkin labels $(2,1)$, $(0,2)$ and $(1,0)$. Convolving the triplet and octet weight diagrams and applying highest-weight character subtraction removes these three characters in that order. Their dimensions $15+6+3=24$ match the product.

// Target: quantum-field-theory.bigb