Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 68 1 b Solution Created 2026-10-03 Updated 2026-10-14
For physical finite-spin one-particle states, a positive-energy Poincaré group representation is labelled by mass and spin when , or mass and helicity when massless. The individual states also carry their four-momentum and a spin projection. For four-dimensional N=1 supersymmetry, the irreducible labels become , with the superspin, or , with a chosen superhelicity convention. The constituent representation labels arewith the last entry omitted for , andA required CPT completion of a supermultiplet adds the conjugate labels and conjugates any internal charges.
Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 53 4 Solution Created 2026-10-03 Updated 2026-10-14
In a massive four-dimensional N=1 supersymmetry representation, the two normalized raising supercharges transform as a spin-half doublet. Start with a Clifford vacuum of superspin . At occupation levels zero, one and two, the ordinary spins areThe two-creation state has a spin-singlet oscillator factor because the creation operators anticommute. Thus the massive N=1 vector multiplet containsThere are four bosonic polarizations, , and four fermionic polarizations, , as required by boson-fermion degeneracy in a supermultiplet.
In the massless limit the helicity multiplicities become , two copies each of , and two zero-helicity states. They separate into the four irreducible helicity pairsWith the lower-helicity convention for superhelicity, a pair has labels , respectively. A midpoint convention shifts each label by ; the explicit helicity pairs remove any naming ambiguity.
Pairing under the CPT theorem, the first and last pairs form a massless vector multiplet, and the middle two form a massless chiral multiplet. This is the massless limit of a massive N=1 vector multiplet. The longitudinal vector polarization supplies one of the chiral multiplet's two real scalar modes; the original spin-zero state supplies the other. Simply discarding the longitudinal polarization would lose a physical degree of freedom and give the wrong decomposition.