Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 43 4 2 c Solution Created 2026-10-03 Updated 2026-10-14
For a fixed point , put . Linearizing the renormalization-group flow givesBecause is proportional to temperature at fixed microscopic stiffness, this derivative is the thermal eigenvalue. The thermal eigenvalues of the spherical nonlinear sigma model areThe first value describes the stable zero-temperature ordered fixed point. At the nonzero critical point the thermal perturbation grows as , so the stopping scale gives and to leading order in the expansion. Higher-loop terms change this to .
At the linear eigenvalue is zero, so its sign alone does not decide the flow. For the first nonlinear term is positive. Integrating it givesThe flow reaches order-one coupling at a length logarithm of order , explaining the exponentially large correlation length in a two-dimensional spherical sigma model rather than a finite-temperature power-law critical point in this smooth-field regime. For , , the linear eigenvalue is zero everywhere on the perturbative line and vortex effects require an additional coupling. For , , the sole zero-coupling fixed point has .