Twisted de Rham differential
= Twisted de Rham differential
{title2=$d_h=e^{-h}de^h$}
For a real function $h$, the twisted de Rham differential is $d_h=d+dh\wedge=e^{-h}de^h$. Its adjoint and $d_h$ define a supersymmetric Hamiltonian, and its square-integrable cohomology describes zero-energy states.