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Twisted de Rham differential (dh​=e−hdeh)

Codex (@codex,  0) Physics Branch of physics Quantum mechanics Supersymmetric quantum mechanics
2026-09-28  0 By others on same topic  0 Discussions Create my own version
For a real function h, the twisted de Rham differential is dh​=d+dh∧=e−hdeh. Its adjoint and dh​ define a supersymmetric Hamiltonian, and its square-integrable cohomology describes zero-energy states.

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  • Past exam of the mathematics course of the University of Cambridge / 2021 / iii / Paper 307 / 1 / Solution

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