Velocity maximum in a one-charged-wall channel
= Velocity maximum in a one-charged-wall channel
{title2=$x_{\max}\simeq\log(\kappa d)/\kappa$}
Differentiating the screened-channel <velocity> gives $x_{\max}=d-\kappa^{-1}\operatorname{arsinh}[(\cosh\kappa d-1)/(\kappa d)]$. For $\kappa d\gg1$, $x_{\max}\simeq\log(\kappa d)/\kappa$. The outer flow declines almost linearly to the passive no-slip wall rather than forming a symmetric plug.