Past exam of the mathematics course of the University of Cambridge 2001 iii Paper 44 4 ii Solution Created 2026-10-03 Updated 2026-10-14
For constant porosity and permeability, the equation is . Under , , , the chain rule gives and . Thus the moving-frame porous medium equation isIts conserved mass is .
There is a source inconsistency in the printed volume formula. Actual liquid volume is . The stated coordinates have Jacobian determinantso the volume Jacobian for downslope stretched coordinates requiresThe printed factor in the first expression is its reciprocal and cannot be proved with these coordinates. For example, at an integral equal to one corresponds to actual volume , whereas the printed formula gives . The physical-volume normalization below uses the corrected Jacobian.
Let . For the source-type axisymmetric similarity solution, putMass conservation imposes , and balancing against gives . Hence and . The profile equation isMultiplying by , the left side is . Integration and regularity at the origin giveWhere , divide by to obtain , soSet the profile to zero beyond this front. The mass normalization isTherefore the two-dimensional Barenblatt profile for quadratic porous-medium diffusion iswhere . Its radius and central thickness areThe profile is regular at the center, its flux vanishes at the dry edge, and the front speed equals the limiting advective speed there. Its support shrinks to the release point as while its mass stays , giving the concentrated initial release in the weak sense.