Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 24 1 ii Solution 2026-10-14
The preceding dimension of level-one modular forms gives and . Thus , which begins with , spans . A normalized weight-sixteen Eisenstein series and both have constant term one, so their difference is a multiple of .
There is a normalization error in the printed auxiliary expansion: for the usual normalized , the coefficient multiplier is , rather than . Indeed, the Fourier expansion of a normalized Eisenstein series gives , and the Bernoulli number gives . The printed multiplier is smaller by a factor of . With the correct normalization, the first Fourier coefficients yieldComparing all positive-index coefficients therefore gives the exact identityThe Fourier coefficients of are integers, as are those of : has its integral divisor-sum expansion and the modular discriminant has the product . Also , and . Reducing the identity modulo and cancelling the invertible multiplier proves the weight-sixteen Eisenstein congruenceThe desired congruence is valid; it is the auxiliary normalization in the PDF that requires correction.