The code <code>f(x) + 1</code> should be <code>f(x) + 2</code>

The code `f(x) + 1` should be `f(x) + 2`

I can't believe you got such a basic fact wrong!

1+1<svg width='400em' height='1.08em' viewBox='0 0 400000 1080' preserveAspectRatio='xMinYMin slice'><path d='M95,702
c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14
c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54
c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10
s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429
c69,-144,104.5,-217.7,106.5,-221
l0 -0
c5.3,-9.3,12,-14,20,-14
H400000v40H845.2724
s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7
c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47z
M834 80h400000v40h-400000z'/></svg>​=3, not 2 as mentioned

$\sqrt{1 + 1} = 3$, not 2 as mentioned

This is a section about Atomic orbital!

Atomic orbital is a very important subject about which there is a lot to say.

For example, this sentence. And then another one.


 Score	# id	 Title	 Author	 Comments	Created	Updated
	#2	The code `f(x) + 1` should be `f(x) + 2`	Barack Obama 11	2	2022-11-02	2024-05-21
	#1	$1 + 1 = 3$ , not 2 as mentioned	Donald Trump 29	1	2022-11-02	2024-05-21

 Discussion on "Atomic orbital" by Barack Obama (@barack-obama, 11)