Incoming links: CAPTCHA
CIA 2010 covert communication websites cqcounter Created 2025-04-05 Updated 2025-07-16
cqcounter.com has an exceptionally complete database containing:
- domains
- IP of the domain in the past e.g. cqcounter.com/whois/site/activegaminginfo.com.html which actually contains the IP 66.175.106.148!
- 727 x 545 screenshots from the past e.g. at: cqcounter.com/whois/www/activegaminginfo.com.html. These were also presumably meant to show as a thumbnail on the main page: cqcounter.com/whois/www/activegaminginfo.com.html but don't because it's buggy. It's not as good as the HTML from Wayback machine as we can't confirm comms like that, but still this can d help to verify if known in-range domains that the wayback machine didn't archive well (because it is buggy as hell?) have correct style and if they have anything fun in them. We are storing:
- a backup of the screenshots at: github.com/cirosantilli/media/tree/master/cia-2010-covert-communication-websites/screenshots/cqcounter
- a list of their source URLs at: github.com/cirosantilli/media/blob/master/cia-2010-covert-communication-websites/cqcounter-images.txt This should be merged into hits.json but we are lazy.
And perhaps due to having lots of CAPTCHAs, Google doesn't seem to index that website very well... it even has a tiny screenshot! And it also shows some more metadata beyond IP, e.g. HTTP response headers, which notably contain stuff like
Server: Apache-Coyote/1.1.They seem to have an exceptionally complete database.
Both cqcounter.com/whois/www/teclafinance.com.html and cqcounter.com/whois/site/activegaminginfo.com.html both are broken, so it appears that their screenshot mechanism at the time did nor support Chinese characters well.
They also have some random localized versions:These can be useful if your IP gets blacklisted on the main site because you were checking too many sites.
Project Euler problem zero Created 2025-10-14 Updated 2025-10-27
This was a registration CAPTCHA problem as of 2025:Python solution:At: euler/0.py
Among the first 510 thousand square numbers, what is the sum of all the odd squares?
s = 0
for i in range(1, 510001, 2):
s += i*i
print(s)