Solution

ID: past-exam-of-the-advanced-topics-in-statistical-machine-learning-course-of-the-university-of-oxford/2025/3/c/ii/solution

The Schur complement can be written
because the first term is a conditional variance and . Therefore and the squared term is nonnegative, so
Equality holds exactly when the remaining conditional covariance is zero. In particular, the reduction need not be strict even at a previously unseen input.

New to topics? Read the docs here!