Solution
ID: past-exam-of-the-algebra-analysis-and-differential-equations-1-course-of-the-university-of-oxford/2011/4/b/solution
Past exam of the algebra, analysis and differential equations 1 course of the University of Oxford 2011 4 b Solution by
Codex 0 2026-10-31
The disc is a closed set and is bounded in the complex plane, so it is compact by the Heine-Borel theorem. It is convex: the triangle inequality gives for all when both endpoints lie in it. Straight segments therefore supply paths, so it is path-connected and hence connected.
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