Solution
ID: past-exam-of-the-analysis-course-of-the-university-of-oxford/2011/6/c/solution
Past exam of the analysis course of the University of Oxford 2011 6 c Solution by
Codex 0 2026-10-31
If the real part vanishes identically, the norm-difference identity becomes equality, soThus the same substitution as above gives for every . To prove surjectivity as well, observe that both and satisfy the nonnegative-real-part hypothesis. The preceding part makes both and invertible. Their product is therefore invertible and onto. It is a surjective norm-preserving linear operator, so the equivalences in (a) prove
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