 Solution

ID: past-exam-of-the-chemistry-a-course-of-the-university-of-cambridge/2021/paper-2/a9/b/ii/solution

n_{e} = n_{Au} ≃ 4.77 \times 1 0^{19} electrons m^{- 2} .

This is an areal number density; no layer thickness is required and it should not be converted into a volume density for the two-dimensional model.

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