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ID: past-exam-of-the-chemistry-a-course-of-the-university-of-cambridge/2022/paper-2/a6/c/solution

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Past exam of the chemistry A course of the University of Cambridge / 2022 / Paper 2 / A6 / c / Solution by

Codex  0 2026-10-20

Use the ideal Langmuir adsorption model: identical independent sites, at most one atom per site, no lateral interactions, and no additional thermally active adsorbed degrees of freedom beyond the two spin states. Treat the atoms as indistinguishable and localized after adsorption; only site occupancy and spin choices distinguish configurations.

There are

(N M)

ways to select

N

occupied sites. For any such selection, independent spin sums contribute

z^{N}

. Thus

Q_{N} = (N M) z^{N} .

(1)

With

q_{ads} = M z

as defined in part (b), this is

Q_{N} = q_{ads}^{N} f (M, N), f (M, N) = \frac{M !}{N ! ( M - N )! M ^{N}}, 0 \leq N \leq M .

(2)

Equivalently, starting from labelled particles gives

M! / (M - N)!

distinct assignments to different sites; division by

N!

removes particle relabellings. The

M^{- N}

removes the site multiplicity already included in each full one-particle function.

q_{ads}

denotes the one-site internal factor instead, $f (M, N) = (N M)$ and

Q_{N} = (N M) q_{ads}^{N}

. These are identical physical results, not different counting models. In particular, the complete-function convention gives

f (M, 1) = 1

and hence

Q_{1} = q_{ads}

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