Solution

ID: past-exam-of-the-chemistry-b-course-of-the-university-of-cambridge/2021/paper-2/b9/e/i/solution

First count the organic groups and then the unsatisfied oxygen valences. A is the fully condensed T8 silsesquioxane cage, , with silicon at the eight vertices of a cube and bridging oxygen on its twelve edges. Each silicon has one cyclohexyl group and three siloxane bridges. Its eight cyclohexyl groups supply exactly .
B is a fully condensed T10 silsesquioxane cage, , for which a pentagonal-prismatic silicon skeleton with an oxygen on every edge is a standard compatible structure. Its ten groups give . The formula establishes full condensation but does not, without more structural data, rule out every other possible ten-vertex cage connectivity.
C is a corner-deficient T7 trisilanol cage, . Seven cyclohexyl groups account for , leaving three hydrogen atoms as Si–OH groups. Remove one silicon corner of the T8 cube and replace the three severed connections by terminal hydroxyl groups. Nine oxygen atoms remain as bridges and three become terminal silanol oxygen atoms, giving precisely twelve oxygen atoms. There are three silicon sites bearing OH, three further equivalent fully condensed sites, and one opposite fully condensed site, consistent with three silicon environments in a 3:3:1 site-count ratio. The less negative resonance is naturally associated with the three silanol-bearing sites; the remaining two resonances belong to the two fully condensed classes. Peak heights alone are not quantitative integrations.
Figure 1.
Silicon skeletons of the T8, T10 and corner-deficient T7 cages
. Details.
The source figure appears to label the spectrum . The chemically appropriate routine experiment here is silicon-29 NMR, using the spin-one-half isotope ; the figure label is treated as an apparent isotope-label typographical error, not as evidence for another cage.

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