 Solution

ID: past-exam-of-the-chemistry-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2022/paper-1/5/c/i/solution

At the higher temperature the same equilibrium rate balance gives

k_{- 1}^{'} = \frac{k _{1}^{'}}{K _{318}} = \frac{1.04 \times 1 0 ^{- 3}}{2.31} = 4.50 \times 1 0^{- 4} s^{- 1} .

This is a reverse first-order rate constant, not the net relaxation rate, which includes both elementary directions.

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