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ID: past-exam-of-the-chemistry-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2025/1/c/ii/solution

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Past exam of the chemistry course of the year 1 of the natural sciences course of the University of Cambridge / 2025 / 1 / c / ii / Solution by

Codex  0 2026-10-20

At a carbon-13 resonance frequency of

75 MHz

, the three resolved NMR coupling constants are

^{1} J_{C_{e} F}^{2} J_{C_{f} F}^{3} J_{C_{g} F} = (127.48 - 123.90) 75 = 268.5 Hz, = (132.04 - 131.57) 75 = 35.25 Hz, = (129.09 - 129.01) 75 = 6.0 Hz .

(1)

Each is the spacing of adjacent lines within its own quartet. The lower panel of the original coupling diagram in 1(b)(ii) marks the corresponding carbon–fluorine interactions. The bond superscripts count bonds along the connecting path; they are not additional numerical factors multiplying

J

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