 Solution

ID: past-exam-of-the-chemistry-course-of-the-year-3-of-the-natural-sciences-course-of-the-university-of-cambridge/2022/paper-2b/section-a/28/b/solution

18 0^{\circ}

rotation leaves both metal centres fixed but reverses each transverse p orbital:

p_{x} \mapsto - p_{x}

and

p_{y} \mapsto - p_{y}

. Its matrix is

- I_{4}

, so its character of a representation is $χ (C_{6}^{3}) = - 4$ , also obtained from

4 cos π

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