Solution

ID: past-exam-of-the-chemistry-course-of-the-year-3-of-the-natural-sciences-course-of-the-university-of-cambridge/2022/paper-3/49/c/iv/solution

The relevant decomposition is unchanged:
Thus the same and vibrational symmetries are linearly Jahn-Teller active. Their coupling constants and the resulting energy surface can differ from those of a state. The ground-geometry methane normal-mode representation and the symmetry-allowed harmonic invariants are also unchanged; actual force constants in the excited state need not have the same values.

New to topics? Read the docs here!