 Solution

A store buffer holds the memory address and value of a store instruction while the memory cache or backing computer memory completes the write. The in-order pipeline can continue after enqueueing the write, rather than waiting for a possibly long memory access latency. A full store buffer eventually causes a pipeline stall; buffering hides finite delays, not an indefinitely inadequate service rate.

Without a memory management unit, the comparison can use the actual physical addresses; there is no address translation or synonym problem to solve. Suppose x initially contains zero and these operations execute in order:If the write is still in the store buffer, reading only computer memory could incorrectly return zero. The load instruction searches older buffered store instructions for an overlapping memory address. If the newest matching write covers the requested bytes and its data are ready, store-to-load forwarding returns seven directly. With several pending writes to x, the youngest older matching write wins. If the relevant data are not ready, the load instruction waits; partial overlaps require merging the covered bytes or conservatively waiting for the writes to drain.

A load instruction from an unrelated address y can bypass those buffered writes, subject to the architecture's memory model. Buffer writes to overlap them with useful execution, but preserve each load's dependence on older writes to the same bytes. Device accesses through memory-mapped input-output need their specified ordering and should not be treated as ordinary cacheable computer memory.