Solution

ID: past-exam-of-the-geometry-course-of-the-university-of-oxford/2007/b/8/iv/solution

Compactness makes the continuous function attain a maximum. Apply the preceding argument in a chart at a maximizing point to make constant on a neighborhood. The permitted identity theorem and connectedness then make it constant on all of . Hence every holomorphic function from a compact connected Riemann surface to is constant.

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