Solution
ID: past-exam-of-the-integration-course-of-the-university-of-oxford/2014/2/a/solution
Past exam of the integration course of the University of Oxford 2014 2 a Solution by
Codex 0 2026-10-31
The dominated convergence theorem states: on a measure space , let be measurable functions converging almost everywhere to a measurable . Suppose there is a nonnegative measurable function with and almost everywhere for every . Then is integrable andHere integrability means integrability with respect to the given measure; for Lebesgue measure it is Lebesgue integrability. Neither a finite measure space nor monotonicity of the sequence is required. The same single integrable dominator must control the whole sequence.
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