Solution

ID: past-exam-of-the-lie-groups-and-differentiable-manifolds-course-of-the-university-of-oxford/2008/a/4/b/solution

Schur orthogonality for irreducible complex characters of a compact group, with normalized Haar measure, is
Equivalent representations clearly have equal characters, since trace is invariant under conjugation. Conversely complete reducibility gives , where the nonnegative integer multiplicity is recovered by . Equal characters thus give equal multiplicities of every irreducible constituent, hence equivalent representations.

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