Two vectors are orthogonal when their inner product is zero.
For real Euclidean vectors, the inner product is the dot product, so and are orthogonal: . For nonzero Euclidean vectors, this means their angle is . The zero vector is orthogonal to every vector, although it has no direction or defined angle.[ref]
https://ocw.mit.edu/courses/18-06-linear-algebra-spring-2010/resources/lecture-14-orthogonal-vectors-and-subspaces/. Strang, MIT 18.06, Lecture 14: orthogonal vectors and subspaces
In an abstract inner product space, orthogonality always refers to its chosen inner product. For example, the weighted inner product makes and orthogonal, since . Their ordinary dot product is , so their arrows are not perpendicular in the usual Cartesian coordinate system. The algebraic definition also applies to functions, where arrows need not be available.
A finite collection of nonzero pairwise orthogonal vectors is linearly independent. Given , take the inner product with to obtain . Positive definiteness and force for every index. The nonzero condition matters: adjoining a zero vector preserves pairwise orthogonality but destroys linear independence.
In the Hilbert space , choose orthonormal functions and . Their inner product is zero, but for the real potential energy ,Thus ordinary orthogonality alone does not remove an off-diagonal matrix element of a spatially varying potential energy. A constant scalar potential does give zero between distinct orthonormal states. The example separates these two claims; it is not a model of localized atomic orbitals in a particular crystal.
An orthogonal basis of an inner-product vector space consists of nonzero mutually orthogonal vectors that span the space. The orthogonal projection of onto a finite-dimensional span is . Dividing each vector by its norm produces an orthonormal basis. For centered random variables, the inner product is covariance; an orthogonal basis therefore consists of uncorrelated variables, without requiring unit variance.
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