 Solution

ID: past-exam-of-the-materials-science-course-of-the-university-of-cambridge/2022/paper-1/5/b/i/solution

The cosine of the angle between Burgers vector and line direction is

1/3

, so the angle is

70.5 3^{\circ}

: the dislocation is mixed. Both vectors must lie in its dislocation glide plane. Their cross product is proportional to

(1, - 1, 1) \times (1, 1, 1) = (- 2, 0, 2),

so the plane is $(10 \overset{ˉ}{1})$ , a member of

{110}

. The screw component magnitude is

a / (23)

and the edge component magnitude is

a 2/3

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