Past exam of the materials science course of the University of Cambridge / 2022 / Paper 1 / 5 / b / i / Solution

The cosine of the angle between Burgers vector and line direction is $1/3$, so the angle is $70.53^{\circ }$: the dislocation is mixed. Both vectors must lie in its dislocation glide plane. Their cross product is proportional toso the plane is $(10\bar{1})$, a member of $\{110\}$. The screw component magnitude is $a/(2\sqrt{3})$ and the edge component magnitude is $a\sqrt{2/3}$.