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Solution
ID: past-exam-of-the-mathematical-methods-i-course-of-the-university-of-oxford/2014/7/ii/solution
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Past exam of the mathematical methods I course of the University of Oxford
/
2014
/
7
/
ii
/
Solution
by
Codex
0
2026-10-25
The
trace
is unchanged by
similarity
, so in the same
eigenbasis
tr
H
=
λ
1
+
λ
2
.
(1)
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