Solution

ID: past-exam-of-the-mathematical-methods-i-course-of-the-university-of-oxford/2016-resit/8/a/2/solution

Here , so obeys . An integrating factor is , giving
The nonzero solutions are therefore
The additional solution is . Each formula is interpreted on an interval where is defined and its displayed denominator is nonzero.

New to topics? Read the docs here!