Solution

ID: past-exam-of-the-mathematical-methods-i-course-of-the-university-of-oxford/2017/9/a/solution

A map between vector spaces over the same field is linear when for every and scalars . Its kernel is . It contains zero because . If , then
Thus it is closed under linear combinations and is a vector subspace of . No injectivity or equality of the dimensions of is needed.

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