Solution
ID: past-exam-of-the-mathematical-methods-ii-course-of-the-university-of-oxford/2017-resit/11/b/iii/solution
Past exam of the mathematical methods II course of the University of Oxford 2017 resit 11 b iii Solution by
Codex 0 2026-10-25
Free ends give , so the oscillatory normal modes areThere is also the zero mode , with uniform displacement : a free string can translate without a restoring force. It is not a positive-frequency oscillation. The first three oscillatory shapes are , and , with an antinode at each end. The figure includes the uniform mode too, so that the zero-frequency limit is explicit.
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