 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2005/ib/paper-4/19d/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-10-14

β = β + \frac{\sum _{i} x _{i} ϵ _{i}}{S _{xx}} .

β

and its variance is

σ^{2} \sum_{i} x_{i}^{2} / S_{xx}^{2}

. Hence

β \sim N (β, \frac{σ ^{2}}{S _{xx}}) .

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