Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2005/ii/paper-4/25j/solution

The Fubini theorem for an integrable Borel-measurable function states that, if , its sections are integrable for almost every coordinate and
For a nonnegative measurable function, Tonelli theorem gives the same equalities with infinity allowed before integrability is established.
Here is the continuous exponential multiplied by the indicator of a Borel set, so it is Borel-measurable and nonnegative. Tonelli and integration in give
This proves integrability. We may now integrate in the reverse order; for the inner integral is . Hence the Frullani integral is
The apparent singularity at zero is removable in the integrand's limiting value .

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