Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2006/ib/paper-2/4f/ii/solution
Past exam of the mathematics course of the University of Cambridge 2006 ib Paper 2 4F ii Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-14
Factorization gives or . Each point can be joined to the origin by a straight segment lying on its own line. Two such segments join any pair of points, so the union is path-connected and hence connected. Alternatively it is the union of two connected lines with a common point.
New to topics? Read the docs here!