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Past exam of the mathematics course of the University of Cambridge / 2006 / ib / Paper 2 / 4F / ii / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2006 ib Paper 2 4F ii
Created 2026-09-24 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
Factorization gives y=x or y=−x. Each point can be joined to the origin by a straight segment lying on its own line. Two such segments join any pair of points, so the union is path-connected and hence connected. Alternatively it is the union of two connected lines with a common point.

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