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ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2006/iii/paper-45/2/f/solution
Past exam of the mathematics course of the University of Cambridge 2006 iii Paper 45 2 f Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-14
Family comparisons condition on the parental genotypes, so cases are compared with the alleles they could have inherited. This protects a transmission test from ordinary population stratification, avoids having to recruit unrelated controls matched for ancestry, and can resolve haplotypes and identify Mendelian inconsistencies. The same pedigree may also provide linkage information.
The costs are recruiting and genotyping relatives, missing or unavailable parents, and fewer informative comparisons because homozygous parents contribute no transmission contrast. These problems are especially important for late-onset disease. Related cases or multiple siblings also require an analysis accounting for dependence, and genotyping error or transmission distortion can mimic overtransmission. Population-based case/control studies are usually easier to assemble and can offer greater power per genotyped person, but need careful control of ancestry and other sources of confounding. Family sampling does not remove every form of ascertainment in a genetic study or observation bias.
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