Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2007/iii/paper-23/4/solution
Past exam of the mathematics course of the University of Cambridge 2007 iii Paper 23 4 Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-14
Write . A dualizing sheaf on a smooth projective curve, for the vector bundles in this question, consists of a line bundle and a trace making evaluation induce natural perfect pairingsIn particular it represents the functor through . We construct it by reducing to the proved residue duality on the projective line.
Choose a separating nonconstant rational function on . Such a choice exists over any field : the function field of a smooth algebraic curve is separably generated of transcendence degree one, and a choice with makes its finite extension of separable. The map extends across poles using in the discrete valuation ring at each point. It gives a finite generically separable morphismIndeed it is nonconstant, hence has finite fibres, and is proper; a proper quasi-finite morphism is finite. This finite map is flat: locally its direct-image module is finite and torsion-free over a discrete valuation ring, and hence free. The same argument works componentwise if needed.
For an affine chart with inverse image , form the -moduleThese modules glue to the relative trace-dual sheaf on . There are two algebraic identities used here. First, finite-map adjunction givesThe forward map evaluates at ; the inverse sends to . Second, the different–differential identity for a finite generically separable map between smooth curves givesTo explain its algebraic content, the field trace identifies with the inverse different ideal, while the different is the vanishing ideal of . These identities include wild ramification; one must not replace the different by just ramification index minus one. This is the identity allowed to be quoted in the question; the finite-map description is recorded in Stacks Project, finite morphisms, and its differential form in Stacks Project, Section 53.12.
Set . The second identity shows it is a line bundle and already identifies it with . For a vector bundle , the first identity gives the sheaf isomorphismThe sheaf is locally free: on an affine chart, the projective -module defining is a summand of , and is finite free over . Since is finite, affine-cover Čech cohomology identifies with for each of these sheaves. Apply the already established duality on to . It givesThe trace is obtained by evaluating the trace-dual module at and then using the trace . The adjunction formulas show the displayed isomorphisms are induced by evaluation against this trace and are natural in . They thus establish the requested dualizing property, not merely the existence of an invertible differential sheaf. Uniqueness follows from the Yoneda lemma applied to the representing functor on vector bundles.
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