Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2007/iii/paper-3/2/solution

The Brauer first main theorem says that, for a fixed p-subgroup and , there is a bijection between blocks of a group algebra of with defect group of a block and blocks of with that defect group. Correspondents have the same nonzero image under . The integral version follows by modular reduction of block idempotents.
Here is a proof using relative traces. Put and
The latter ambient algebra is commutative because invariance under includes invariance under . The Brauer morphism and relative trace identity is
Indeed acts on . Its fixed cosets are exactly . On a nonfixed orbit the terms have the same Brauer image, so the orbit contributes zero in characteristic . The fixed cosets give the right-hand side. Since every element of is -fixed, this proves that is a surjective algebra homomorphism of commutative ideals. The same argument for has exactly the same target.
We use the following elementary fact about primitive idempotents under a surjection of commutative Artinian ideals. Under a surjection of ideals in finite-dimensional commutative algebras, the primitive ambient idempotents lying in and having nonzero image correspond bijectively to the primitive idempotents in . To prove it, decompose the source ambient algebra into Artinian local rings . Either , or it is a proper, hence nilpotent, ideal. Proper components contribute no idempotents to the image. A surviving identity has corner , a local quotient of , so is primitive. The surviving identities are orthogonal and exhaust the idempotents of the target. Notice that this proof does not assert that the whole kernel is nilpotent: it can kill entire block components.
By the trace criterion for defect groups proved above, primitive block idempotents in have defect conjugate into . Among them, the Brauer morphism is nonzero precisely for defect , again by that criterion and its Brauer characterization. The identical reasoning applies to . Thus both sets are identified with the primitive idempotents of , proving the bijection and its uniqueness.
For the more general subgroup, is understood to be a defect group of a block of . This is the implicit hypothesis needed to apply the theorem; it is not repeated in the printed sentence. Without it the printed uniqueness assertion is false: take , , and . The centralizer of in is , but the unique three-dimensional defect-zero block of is the bimodule restriction of each of the two three-dimensional defect-zero blocks of . The two ordinary degree-three characters both restrict to the degree-three character of , with values on its identity, involutions and elements of order three. Defect-zero reduction gives the same simple projective -module, so both restricted block bimodules are this same matrix block. This illustrates why block induction requires the block's defect centralizer. Write for its block idempotent and . Since , we have . Apply the theorem inside to obtain the unique corresponding block of . Its center of an associative algebra has a residue field , and the quotient map is its central character of a block . No assumption that is algebraically closed is needed here. Define
The Brauer image is in , so this is a unital algebra homomorphism. Among the orthogonal primitive central idempotents of , exactly one has image . The block it selects is . If contains this is the inverse of the bijection just proved. For arbitrary , the resulting block can have a strictly larger defect group. Block induction is transitive on admissible intermediate subgroups. For the normalizer chain used in the proof below, the required transitivity will be verified directly with Brauer images.
To prove the bimodule characterization, we explicitly state the standard permutation-module fact used here. For a permutation module, the Brauer quotient of a module at has as basis the permutation-basis points fixed by . An indecomposable summand has nonzero quotient at exactly when its vertex of an indecomposable module contains a conjugate of . For summands with vertex exactly , taking this quotient, with its -action, detects the summand and detects which orthogonal idempotent projection acts as its identity. These facts hold for trivial source modules; the fixed-basis description follows by deleting proper transfers, and the detection assertion is the permutation form of the first-main-theorem argument, applied to their endomorphism algebra.
As an permutation module, with , the group algebra decomposes as
The block bimodule is an indecomposable module with vertex of an indecomposable module . None of the other double-coset modules can contain : a basis element fixed by centralizes , hence lies in , whereas those double cosets lie outside . Thus occurs exactly once as an indecomposable summand of this restriction, in the term. Decomposing into its global block bimodules therefore puts this occurrence in precisely one of them, say .
Under the fixed-basis description, the quotient of at is , and multiplication by induces multiplication by . The quotient of is . Consequently the detecting projection for this occurrence of satisfies
which is equivalent to . Thus , proving the requested unique-block direct-summand characterization. Here the restriction is to ; the extra subscript in the converted TeX is a transcription error, not a different subgroup.

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