Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2008/iii/paper-13/2/c/solution

The required functional, with the sign appropriate to a positive divergence operator, is
It is differentiable on , with . A critical point consequently satisfies the weak equation. We now prove existence by the direct method in the calculus of variations, rather than invoke the representation theorem again.
The ellipticity and Poincare estimates imply
Thus the infimum is finite and any minimizing sequence is bounded in the Sobolev norm. A bounded sequence in a Hilbert space has a weakly convergent subsequence; write in . The equivalent norm has the same continuous linear functionals and hence the same weak convergence. A Hilbert norm is Weak lower semicontinuity, giving . The term converges to because it is a bounded linear functional. Therefore
The limit attains the infimum. Differentiating at its minimum, for every , gives . This produces the desired weak solution. Strict positivity of also makes the functional strictly convex, consistent with uniqueness.

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