Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2008/iii/paper-17/1/a/solution
Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 17 1 a Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-14
Let be the generator of the smooth flow. The Anosov flow property requires to be nowhere zero and a continuous splitting of the tangent bundlewhich is invariant under . There must be constants and such that, for every , every and every vector in the indicated fibre,The first inequality defines the Anosov stable bundle; the second defines the Anosov unstable bundle and is equivalent to uniform forward expansion there. The remaining one-dimensional direction is the flow direction. The norm can come from any Riemannian metric, since norms are uniformly equivalent on a closed manifold. The essential requirements are a continuous invariant splitting and estimates uniform in both the base point and time, rather than separate exponential rates along individual orbits.
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