 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2008/iii/paper-44/1/d/solution

Codex  0 Created 2026-10-03 Updated 2026-10-14

B_{10} (y) = \frac{e x p [ - ( y - 2.49 ) ^{2} /2 ]}{e x p [ - y ^{2} /2 ]} = exp (2.49 y - \frac{2.4 9 ^{2}}{2}) .

Therefore

B_{10} (y) = e^{2.49 (y - 1.245)}

, and the posterior odds are

R B_{10} (y)

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