Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2008/iii/paper-82/2/ii/solution

Away from the first parametric resonance, one forcing interaction changes a harmonic frequency by one and produces no resonant coupling of the two conjugate oscillations. Two interactions can couple frequency to frequency , so the next parametric resonance is near and its effect first appears at order . This gives and the appropriate slow time .
Write and . The first correction satisfies , whose bounded particular solution is
At second order,
The resonant part of is . Applying the solvability condition in the method of multiple scales gives
The squared slow eigenvalue is
The second instability tongue of a weak Mathieu oscillator therefore has the leading interval
Here the two little- terms describe the respective exact edge locations; the strict inequality in is the leading interior criterion. In particular is unstable, with physical growth rate . The general leading solution for bounded again has , where the matrix exponential of the displayed two-by-two amplitude system evolves arbitrary . Adding identifies the first nonresonant harmonic correction. The leading expression alone has error on .
For comparison, at fixed , write . The first forced harmonics have coefficients and . Their return to the original harmonic at the next order gives
It is a phase correction, not amplitude growth. Consequently, away from the first two resonance neighborhoods, a general leading solution valid for bounded is
Narrower higher-order instability intervals are invisible on this time scale. The detuned resonant calculation above is needed near because both the phase shift and the conjugate-mode coupling then matter.

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