Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2009/ii/paper-2/7e/ii/solution

Now . The zero point exists for all parameters and has eigenvalue , so it is stable for and unstable for . At every nonzero fixed point,
Both outer branches are stable and both inner branches unstable.
For , the nonzero locations are as in part (i). At the local equation is : these are subcritical pitchfork bifurcations, with the two unstable inner branches present on the side where zero is stable. At the bifurcation itself , so zero is unstable. At the inner and outer branches cross and exchange stability in transcritical bifurcations. The positive crossing is semistable, attracting from the right; the negative crossing is semistable, attracting from the left, because the additional factor reverses the local flow there.
For , the outer stable pair exists only for . The points are supercritical pitchfork bifurcations, since the cubic coefficient is negative. Zero loses stability as increases across , and a stable symmetric pair appears. At the threshold zero remains nonlinearly stable, with . There are no further bifurcations. The second row of the preceding figure gives the diagrams. The plots use ; the general locations are obtained from the formulas above.

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