Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2009/iii/paper-56/2/d/ii/solution
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 56 2 d ii Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-14
On the equatorial plane, the Kerr metric coefficient simplifies toPut on the negative-radius sheet. Then for all sufficiently small . The curveis a closed timelike curve, since its tangent is and the angular coordinate is periodic. It never meets the ring at . These are the closed timelike circles in negative-radius Kerr spacetime; they need not be geodesics. Along them is also constant, because its difference from depends only on .
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