Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2011/ii/paper-1/26k/iv/solution

Finite independent Gaussian sums are Gaussian; directly, multiplication of their characteristic functions gives
By Markov inequality, . Part (ii) makes the same sequence converge in distribution to , and the characteristic-function estimate there makes . Uniqueness of distributions determined by characteristic functions therefore yields
If , all coefficients vanish and almost surely; here denotes that degenerate distribution.

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