Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2011/ii/paper-3/1i/i/solution
Past exam of the mathematics course of the University of Cambridge 2011 ii Paper 3 1I i Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-14
Lagrange theorem for polynomial congruences says that a nonzero polynomial of degree over a field has at most distinct roots of a polynomial. It follows by repeatedly factoring out at a root. Over the finite field , the only solutions of are and : these are distinct because is odd, and the root bound excludes any others.
Every nonzero element has a unique multiplicative inverse. Pair each element of with its inverse. All pairs of distinct elements contribute to the product; the only unpaired elements are and . Thus Wilson theorem follows:If Lagrange's theorem is formulated for finite groups, it states that the order of a subgroup divides the order of the group; in particular every element of has order dividing . The inverse-pairing proof above establishes the required congruence directly.
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